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Byju's Answer

Standard XII

Chemistry

Hydrides of Group 16

H2S precipita...

Question

$H_{2} S$ precipitates aqueous $Z n C l_{2}$ solution in :

Acidic medium.

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Neutral medium.

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Both (a) and (b).

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None of these.

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Solution

The correct option is A Neutral medium.
As solubility product of ZnS is very high so in acidic medium precipitate doesn't form but in neutral medium precipitate forms as $Z n C l_{2} + H_{2} S \to 2 H C l + Z n S$ .

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Similar questions

Q. Assertion :When

H_{2} S (g)

is passed into aqueous

{Z n C l}_{2}

, solution,

Z n S

is precipitated. Reason:

Z n S

is insoluble in dil.

H C l

An aqueous solution of a mixture of two inorganic salts, when treated with dilute

H C l

, gave a precipitate (P) and filtrate (Q). The precipitate P was found to dissolve in hot water.

The filtrate (Q) remained unchanged, when treated with

H_{2} S

in dilute mineral acid medium. However, it gave a precipitate (R) with

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in an ammoniacal medium. The precipitate R gave a coloured solution (S ), when treated with

H_{2} O_{2}

in an aqueous NaOH medium.

The coloured solution S contains:

Q. Assertion :When

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gas is passed into an aqueous solution of

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ions are completely precipitated as zinc sulphide. Reason: Zinc sulphide is insoluble in solutions of caustic alkali but dissolves in dilute

H C I

An aqueous solution of a mixture of two inorganic salts, when treated with dilute HCl, gave a precipitate (P) and a filtrate (Q). The precipitate (P) was found to dissolve in hot water. The filtrate (Q) remained unchanged when treated with $H_{2} S$ in a dilute mineral acid medium. However, it gave a precipitate (R) with $H_{2} S$ in an ammoniacal medium. The precipitate R gave a coloured solution (S) when treated with $H_{2} O_{2}$ in an aqueous NaOH medium.

The precipitate P contains

Q. Passing

H_{2} S

gas into a mixture of

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and

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H2S precipitates aqueous ZnCl2 solution in :

The correct option is A Neutral medium.As solubility product of ZnS is very high so in acidic medium precipitate doesn't form but in neutral medium precipitate forms as ZnCl2+H2S→2HCl+ZnS.

$H_{2} S$ precipitates aqueous $Z n C l_{2}$ solution in :

The correct option is A Neutral medium.
As solubility product of ZnS is very high so in acidic medium precipitate doesn't form but in neutral medium precipitate forms as $Z n C l_{2} + H_{2} S \to 2 H C l + Z n S$ .