Question

$H_{2}S{O}_4\left(98gmo{l}^{-1}\right)$ is 98% by mass of solution, if the density is 1.8 g/mL, the molarity is:

Answer 1

Assuming 100 g of the solution
The density of the solution is = 1.8 g / mL
The volume of the solution = $\frac{100}{1.8}$ mL
Mass of $H_{2}S{O}_4$ is 98 g.
number of moles of $H_{2}S{O}_4$ = 1

$\therefore$ Molarity of the solution = $\frac{moles}{\text{volume of the solution in litre}}=\frac{1}{\frac{100}{1.8}}\times 1000=18M$