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Potassium Dichromate

H 2 SO 4 cann...

Question

$H_{2} S O_{4}$ cannot be used to prepare HBr from NaBr as it

A

Reacts slowly with NaBr

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B

oxidises HBr

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C

reduces HBr

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D

disproportionate HBr H₂SO₄

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Solution

The correct option is B
oxidises HBr

HBr is RA and $H_{2} S O_{4}$ is OA and thus , action of NaBr with $H_{2} S O_{4}$ gives bromine in place of HBr

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