CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

H3CCH2CH3|C|HCH2CH3
Maximum numbers of isomers(during stereoisomers) that are possible on monochlorination of following compound is:

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 8
CH3
H3CCH2|C|CH2CH3
H
On monochlorination following possibilities are these.
CH3
(1) H3CCH2|C|CH2CH2Cl 1 chiral centre gives 21 isomers.
H
CH3
(2) H3CCH2|C|CH|CH3
H Cl
As two carbon become chiral thus it will give 22 isomers.
CH3
(3) H3CCH2|C|CH2CH3
Cl
H
(4) H3CCH2|C|CH2CH3
CH2Cl

2 s 4 isomers2R,3R,2R,3S
2S,3R,2S,3S
Thus the total number of isomers= 2+4+2=8 .

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Racemic Mixture
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon