H 3 C - CH - CH 2-1 equiv- Br 2 CCl 4- X alc- KOH - Y - NaNH 2- ZZ is-A- H 3 C - CH - CH 2B- H 3 C - C - CHC- H 3 C - CH 2- CH 2- OHD- CH 3 CH 2 CH 3

The correct option is B H_3C C ≡ CH ...

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Methods for Ester Synthesis

H 3 C - CH = ...

Question

$H_{3} C - C H = C H_{2} + B r_{2} (1 equiv.) C C l_{4} - -- \to X a l c . K O H - ----- \to Δ Y N a N H_{2} - ---- \to Δ Z$

Z is:

H_{3} C - C H = C H_{2}

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H_{3} C - C \equiv C H

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H_{3} C - C H_{2} - C H_{2} - O H

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C H_{3} C H_{2} C H_{3}

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Solution

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H_{3} C - \oplus C H - C H = C H_{2}

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H_{3} C - C H_{2} - C H_{3} | C = C H - C | H C_{2} H_{5} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{3}

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