Question

$H_{3}C-\stackrel{C{H}_3}{\stackrel{|}{\underset{C{H}_3}{\underset{|}{C}}}}-CH=C{H}_2$

The IUPAC name of the compound having the formula is:

• A. $3,3,3-$ Trimethylprop - $1$ - ene
• B. $1,1,1-$ Trimethylprop - $2$ - ene
• C. $3,3$ - Dimethylbut - $1$ - ene
• D. $2,2$ - Dimethylbut - $3$ - ene

Answer 1

The correct option is C $3,3$ - Dimethylbut - $1$ - ene

Reffer image.

In the given compound , first look the

(a) longest chain (which is 4 carbon chain in this case )

(b) give priority to double bond white numbering

(c) choose the number at which methyl group is attached

$\therefore$ Ans $\to$ (c) 3,3 Dimethylbut-1-ene