Question

$H_{3}C-\stackrel{\oplus }{C}H-CH=C{H}_2$ does not involve:

• A. $\sigma -\pi$ overlap
• B. $p\pi -p\pi$ overlap
• C. $p\pi -d\pi$ overlap
• D. All of the above.

Answer 1

The correct option is C $p\pi -d\pi$ overlap

$H_{3}C-\stackrel{\oplus }{C}H-CH=C{H}_2$ in this $\sigma -\pi$ overlapping occurs due to Hyperconjugation and $p\pi -p\pi$ overlap occurs due to resonance but there is no $p\pi -d\pi$ overlap as d-orbital is absent in the molecule. Hence correct option is c.