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Electronegativity

H3C - ⊕CH - C...

Question

$H_{3} C - \oplus C H - C H = C H_{2}$ does not involve:

A

σ - π

overlap

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B

p π - p π

overlap

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C

p π - d π

overlap

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D

All of the above.

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Solution

The correct option is C $p π - d π$ overlap
$H_{3} C - \oplus C H - C H = C H_{2}$ in this $σ - π$ overlapping occurs due to Hyperconjugation and $p π - p π$ overlap occurs due to resonance but there is no $p π - d π$ overlap as d-orbital is absent in the molecule. Hence correct option is c.

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H_{3} C - C H = C H_{2} + B r_{2} (1 equiv.) C C l_{4} - -- \to X a l c . K O H - ----- \to Δ Y N a N H_{2} - ---- \to Δ Z

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The correct IUPAC name of the compound :

Q. Major product of the following

S_{N} 1

Q. Which of the following lone-pair indicated is not involved in resonance?
(A)

C H_{2} = C H - . . N H - C H_{3}

C H_{2} = C H - . . O . . - C H_{3}

C H_{2} = C H - . . O . . - C H = C H_{2}

C H_{2} = C H - N H_{2}

Q. What is the IUPAC name of the following compound?

H_{3} C - C H = C H - C H_{3} | C H_{2}

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Electronegativity

Standard XII Chemistry

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