Question 57 (h)
Add the following expression:
a2+3ab−bc, b2+3bc−ca and c2+3ca−ab
We have, (a2+3ab−bc)+(b2+3bc−ca)+(c2+3ca−ab) On combining the like terms, = a2+3ab−bc+b2+3bc−ca+c2+3ca−ab= a2+b2+c2+3ab−ab−bc+3bc−ca+3ca= a2+b2+c2+2ab+2bc+2ca
Question 57 (c)
ab + bc + ca and - bc - ca - ab