H-C- C-H-H2 A BCHere- C is -

The correct option is C ethanolThe complete reaction sequence is as follows: H C≡ C H+H_2 H_2C=CH_2 C_2H_5Cl C_2H_5OH A is ethene, formed by Lindla ...

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Byju's Answer

Standard XII

Chemistry

Preparation of Alcohols from Alkenes

H-C≡ C-H+H2 A...

Question

$H - C \equiv C - H + H_{2} P d - B a S O_{4} / Q u i n o l i n e - ------------- \to A H C l - - \to B a q . K O H - ---- \to C$
Here, $C$ is :

propane

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ethanol

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ethyne

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ethylene

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Solution

The correct option is C ethanol
The complete reaction sequence is as follows:
$H - C \equiv C - H + H_{2} P d - B a S O_{4} / Q u i n o l i n e - ------------- \to H_{2} C = C H_{2} H C l - - \to C_{2} H_{5} C l a q . K O H - ---- \to C_{2} H_{5} O H$
$A$ is ethene, formed by Lindlar's catalyst.
$B$ is ethyl chloride, formed by the addition of $H C l$ to an alkene.
$C$ is ethanol because alkyl halides react with aqueous $K O H$ to give alcohols.

So, the correct option is B

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X + 2 Z n A l c o h o l \to H - C \equiv C - H

Here X is :

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H - C \equiv C - H + H O C l \to

product, here product will be:

C H_{3} - C \equiv C - C H_{3} H_{2} - ------ \to P d + B a S O_{4} P K M n O_{4} / H^{+} \to Q .

. here the product Q is

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;

Here A is:

C_{2} H_{6} s u n l i g h t - ----- \to {1 M o l e C l}_{2} A a l c . K O H - ----- \to B 200^{0} C - --- \to H_{2} / N i C

Here ‘C’ is :

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H−C≡C−H+H2Pd−BaSO4/Quinoline−−−−−−−−−−−−−−→AHCl−−→Baq. KOH−−−−−→CHere, C is :

$H - C \equiv C - H + H_{2} P d - B a S O_{4} / Q u i n o l i n e - ------------- \to A H C l - - \to B a q . K O H - ---- \to C$
Here, $C$ is :