Question

H.C.F and L.C.M. of two numbers are $17$ and $102$ respectively. If one of the numbers is $34$ find the other.

Answer 1

Since as we know the product of two numbers is equal to the product of its L.C.M and H.C.F.

Formulae $\mathrm{a}\times \mathrm{b}=\mathrm{L}.\mathrm{C}.\mathrm{M}(\mathrm{a},\mathrm{b})\times \mathrm{H}.\mathrm{C}.\mathrm{F}.(\mathrm{a},\mathrm{b})$

Since $\mathrm{a}=34,\mathrm{b}=?,\mathrm{L}.\mathrm{C}.\mathrm{M}=102,\mathrm{H}.\mathrm{C}.\mathrm{F}.=17$

then $34\times b=17\times 102$

$\mathrm{b}=\frac{17\times 102}{34}$

$\mathrm{b}=51$

Hence, other number is $51.$