H.C.F of 45, 30 & 100 is

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Solution

The correct option is D
1

$\begin{matrix} 2 & 30 3 & 15 5 & 5 1 \end{matrix}$
$∴ 30 = 2 \times 3 \times 5$

$\begin{matrix} 3 & 45 3 & 15 5 & 5 1 \end{matrix}$
$∴ 45 = 3 \times 3 \times 5$

$\begin{matrix} 2 & 100 2 & 50 5 & 25 5 & 5 1 \end{matrix}$
$∴ 100 = 2 \times 2 \times 5 \times 5$
$30 = 5 \times 2 \times 3$
$45 = 3 \times 5 \times 3$
$100 = 2 \times 5 \times 5 \times 2$
The common factor is 5
Hence, $H . C . F = (5)$

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