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Question

H.C.F. of two consecutive even numbers is :

A
0
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B
1
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C
4
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D
2
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Solution

The correct option is C 2

Consider two consecutive even numbers. They are of the form 2n,2n+2 for some integer n

2n=2×n

2n+2=2×(n+1)

The numbers n,n+1, being two consecutive integers, are relatively prime

They do not have any factor other than 1 common to them.

Hence HCF of two consecutive even numbers is 2.

So the correct answer is option D


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