H.C.F. of $x^{2} - 1$ and $x^{3} - 1$ is

(x^{2} - 1)^{2}

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(x - 1)

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x+1

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x^{2} + x + 1

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Solution

The correct option is A $(x - 1)$
$x^{2} - 1 = (x + 1) (x - 1)$
$x^{3} - 1 = (x - 1) (x^{2} + x + 1)$
$∴ H . C . F . = (x - 1)$
Option B is correct.

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