H - F form stronger bond than H2O - EN of F - O - H bond - EN- still heat of vapourisation of HF is lower than that of pure water- Why-

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Standard XII

Chemistry

Enthalpy

H - F form st...

Question

$H - F$ form stronger bond than $H_{2} O [∵ E N o f F > O & H b o n d \propto E N]$ still heat of vapourisation of $H F$ is lower than that of pure water. Why?

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Solution

Heat of vapourization depends upon the no. of bonds, not on the strength of signle H-bond,
$1$ molecule of $H F$ can form only $2$ hydrogen bond whereas $1$ molecule of $H_{2} O$ can form $4$ hydrogen bond.

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Similar questions

Q. Which of the following statements is not true for the reaction:

2 F_{2} + 2 H_{2} O \to 4 H F + O_{2}

$A s s e r t i o n - --------- -$ (A): The boiling point of HF is higher than that of $H_{2} O$
$R e a s o n - ------- -$ (R): The hydrogen bond strength in HF is lower than that in $H_{2} O$

Q. Explain why Cl-Cl bond is stronger than F-F bond?

Q. Why is the

H - O - H

bond angle in

H_{2} O

smaller than

H - N - H

bond angle in

N H_{3}

Q. Assertion :

H_{2} S

is more acidic than

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Reason:

H - S

bond is more polar than

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H−F form stronger bond than H2O [∵EN ofF>O&H bond∝EN] still heat of vapourisation of HF is lower than that of pure water. Why?

Heat of vapourization depends upon the no. of bonds, not on the strength of signle H-bond,1 molecule of HF can form only 2 hydrogen bond whereas 1 molecule of H2O can form 4 hydrogen bond.

$H - F$ form stronger bond than $H_{2} O [∵ E N o f F > O & H b o n d \propto E N]$ still heat of vapourisation of $H F$ is lower than that of pure water. Why?

Heat of vapourization depends upon the no. of bonds, not on the strength of signle H-bond,
$1$ molecule of $H F$ can form only $2$ hydrogen bond whereas $1$ molecule of $H_{2} O$ can form $4$ hydrogen bond.