Question

Question 1 (h)

Find the HCF of the following numbers:
91, 112, 49

Answer 1

Factors of 91 = $7\times 13$
Factors of 112 = $2\times 2\times 2\times 2\times 7$
Factors of 49 = $7\times 7$
HCF of 91, 112, and 49 = $1\times 7=7$