Question 66 (h)
Find the value of the given polynomial at a = -2 and b = 3.
a2+b2−ab−b2−a2
Given, a = -2 and b = 3 So, putting a = -2 and b = 3 in the given expression, we get a2+b2−ab−b2−a2=(−2)2+(3)2−(−2)(3)−(3)2−(−2)2=4+9+6−9−4=6
Question 66 (f)
a2−b23
Question 66 (e)
a2+b23
Question 66 (b)
a2−2ab+b2
If a = 2, b = − 2, find the value of:
(i) a2 + b2 (ii) a2 + ab + b2 (iii) a2 − b2
If a + b = 10 and ab = 16, find the value of a2−ab+b2 and a2+ab+b2.