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Atomic Size and Electronegativity

H - H , X - X...

Question

H – H, X – X and H – X bond energies are 104 K cal/mole, 60 K cal/mole and 101 K cal/mole. Assuming the electronegativity of hydrogen to be 2.1 the electronegativity of unknown element ‘X’ is $(\sqrt{19} = 4.36)$

3.5

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2.5

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Solution

The correct option is B 3
$X_{A} - X_{B} = 0.208 \sqrt{Δ}; Δ$ is in Kcal. $m o l e^{- 1}$ .

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Similar questions

H - H

X - X

H - X

104, 60

102

2.1

X

The bond dissociation energy of H - H, C - C, and C - H bonds respectively are 104.2, 83.1 and 98.8 kcal/ mole. The electronegativity of C is?

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{F - F} = 36.6 k c a l m o l^{- 1}

E_{H - F} = 134.6 k c a l m o l^{- l}

X_{H} = 2.1.

E_{H - H} = 104.2 k c a l m o l^{- 1}

E_{C - C} = 83.1 k c a l m o l^{- 1}

E_{C - H} = 98.8 k c a l m o l^{- l}

X_{H} = 2.1.

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