H joules of heat is required to increase the temperature of one mole of a monoatomic gas from 20- C to 30- C at constant volume- How much heat will be required to increase the temperature of 2 moles of a diatomic gas from 20- C to 25- C at constant volume-

For the monoatomic gas Δ H = nC_vΔ T ⇒ H =1 ×3/2R × 10 =15 R For the diatomic gas. Δ H =nC_vΔ T ⇒ H'= 2 ×5/2R × 5 =25 R = 15 R ×25/15 = 15 R ×5/3 = 5/3H ...

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Byju's Answer

Standard XII

Chemistry

Molar and Specific Heat Capacity

H joules of h...

Question

$H$ joules of heat is required to increase the temperature of one mole of a monoatomic gas from $20^{\circ} C$ to $30^{\circ} C$ at constant volume. How much heat will be required to increase the temperature of 2 moles of a diatomic gas from $20^{\circ} C$ to $25^{\circ} C$ at constant volume?

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Solution

For the monoatomic gas
$Δ H = n C_{v} Δ T$
$\Rightarrow H = 1 \times \frac{3}{2} R \times 10 = 15 R$
$R = \frac{H}{15}$
For the diatomic gas.
$Δ H = n C_{v} Δ T$
$\Rightarrow H^{'} = 2 \times \frac{5}{2} R \times 5$
$H^{'} = 25 R = 25 \times \frac{H}{15} = \frac{5}{3} H$ .

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H joules of heat is required to increase the temperature of one mole of a monoatomic gas from 20∘C to 30∘C at constant volume. How much heat will be required to increase the temperature of 2 moles of a diatomic gas from 20∘C to 25∘C at constant volume?

For the monoatomic gas ΔH=nCvΔT⇒H=1×32R×10=15RR=H15 For the diatomic gas. ΔH=nCvΔT⇒H′=2×52R×5H′=25R=25×H15=53H.

$H$ joules of heat is required to increase the temperature of one mole of a monoatomic gas from $20^{\circ} C$ to $30^{\circ} C$ at constant volume. How much heat will be required to increase the temperature of 2 moles of a diatomic gas from $20^{\circ} C$ to $25^{\circ} C$ at constant volume?

For the monoatomic gas
$Δ H = n C_{v} Δ T$
$\Rightarrow H = 1 \times \frac{3}{2} R \times 10 = 15 R$
$R = \frac{H}{15}$
For the diatomic gas.
$Δ H = n C_{v} Δ T$
$\Rightarrow H^{'} = 2 \times \frac{5}{2} R \times 5$
$H^{'} = 25 R = 25 \times \frac{H}{15} = \frac{5}{3} H$ .