Question

Question 58 (h)

Subtract:

2(ab + bc + ca) from -ab - bc - ca.

Answer 1

We have,
-ab - bc - ca - 2(ab + bc + ca)
= - ab - bc - ca - 2ab - 2bc - 2ca
On combining the like terms,
= - ab - 2ab - bc - 2bc - ca - 2ca
= - 3ab - 3bc - 3ca