Question 58 (h)

Subtract:

2(ab + bc + ca) from -ab - bc - ca.

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Solution

We have,
-ab - bc - ca - 2(ab + bc + ca)
= - ab - bc - ca - 2ab - 2bc - 2ca
On combining the like terms,
= - ab - 2ab - bc - 2bc - ca - 2ca
= - 3ab - 3bc - 3ca

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Similar questions

Subtract:

$a b - b c - c a$ from $- a b + b c + c a .$

Question 57 (c)

Add the following expression:

ab + bc + ca and - bc - ca - ab

- a b + b c - c a f r o m b c - c a + a b

In triangle ABC prove AB+BC+CA >2AB

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