H:x2−y2=9 , L:x=9 If L is the chord of contact of the hyperbola H, then the equation of the corresponding pair of tangents is :
A
9x2−8y2+18x−9=0
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B
9x2−8y2−18x+9=0
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C
9x2−8y2−18x−9=0
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D
9x2−8y2+18x+9=0
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Solution
The correct option is B9x2−8y2−18x+9=0 Equation of chord of contact at point (h,k) is xh−yk=0 Comparing with x=9, we get h=1,k=0 So the equation of pair of tangent at (1,0) is SS1=T2 ⇒(x2−y2−9)(1−0−9)=(x−9)2 ⇒9x2−8y2−18x+9=0