Hg(OCOCH3)2. THF / NaBH4. NaOH
The product has been formed according to Markovnikovi addition.
Option (a) would produce a benzylic carbonation.
Option (c) ⇒ Oxymercuration Demercuration
This would have yielded a hydration product according to Markovnikov addition.
Note: Option B gives Anti Markovnikovi product
So Answer Option is C.
(i)Hg(OAc)2⇌+Hg(OAc)+OAc−