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Question


A
H2O / H +
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B

BH3 . THF / H2O2 -OH-

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C

Hg(OCOCH3)2. THF / NaBH4. NaOH

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D

All are possible

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Solution

The correct option is C

Hg(OCOCH3)2. THF / NaBH4. NaOH



The product has been formed according to Markovnikovi addition.

Option (a) would produce a benzylic carbonation.
Option (c) Oxymercuration Demercuration

This would have yielded a hydration product according to Markovnikov addition.

Note: Option B gives Anti Markovnikovi product

So Answer Option is C.

(i)Hg(OAc)2+Hg(OAc)+OAc



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