Question

H₂O₂ acts as what when reacting with ozone?

Answer 1

${\mathrm{H}}_2{\mathrm{O}}_2$ as a reducing agent:

• When hydrogen peroxide $\left({\mathrm{H}}_2{\mathrm{O}}_2\right)$ reacts with Ozone$\left({\mathrm{O}}_3\right)$ the reaction proceeds as follows:

$\underset{(\mathrm{Hydrogen}\mathrm{peroxide})}{{\mathrm{H}}_2{\mathrm{O}}_2\left(\mathrm{l}\right)}+\underset{\left(\mathrm{Oxygen}\right)}{{\mathrm{O}}_3\left(\mathrm{g}\right)}\to \underset{\left(\mathrm{Water}\right)}{{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)}+\underset{\left(\mathrm{Oxygen}\right)}{2{\mathrm{O}}_2\left(\mathrm{g}\right)}$

• As ozone is the better oxidising agent, hence hydrogen peroxide acts as a reducing agent to reduce ozone to oxygen.

Hence, ${\mathrm{H}}_2{\mathrm{O}}_2$acts as a reducing agent when reacting with Ozone.