$H_{2} S + {Cl}_{2} \to S + 2 HCl$ , which substance is: (1) Oxidised (2) Reduced. (3) The oxidising agent (4) The reducing agent. Give reasons?

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Solution

Oxidization:
The process in which oxygen is being added or hydrogen gets removed is called the oxidation process.
Here in the given reaction, $H_{2} S$ which is being oxidized to $HCl$ due to the removal of hydrogen.
Reduction:
The process in which hydrogen is being added or oxygen gets removed is called the Reduction process.
Here in the given reaction, ${Cl}_{2}$ which is being reduced to $HCl$ due to the addition of hydrogen.
Oxidizing agent:
The substance which helps in oxidation and itself gets reduced is called an oxidizing agent.
Here in the given reaction, ${Cl}_{2}$ is the oxidizing agents as, $H_{2} S$ is oxidized by ${Cl}_{2}$ and, ${Cl}_{2}$ itself is being reduced to $HCl$ .
Reducing agent:
The substance which helps in reduction and itself gets oxidized is called a reducing agent.
Here in the given reaction, $H_{2} S$ is a reducing agent as ${Cl}_{2}$ is reduced by $H_{2} S$ and itself is being oxidized to $HCl$ .
Hence, in the given reaction, these substances are : (1) Oxidised - $H_{2} S$ ; (2) Reduced- ${Cl}_{2}$ ;(3) The oxidizing agent- ${Cl}_{2}$ ;(4) The reducing agent- $H_{2} S$ .

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