Question

Haemoglobin contains 0.334 % of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (Atomic weight of $Fe$ is 56) present in one molecule of haemoglobin is:

• A. 4
• B. 6
• C. 3
• D. 2

Answer 1

The correct option is A 4

Weight of $Fe$ in haemoglobin
$=\frac{0.334}{100}\times 67200=224.48\text{u}$
Mass of one $Fe$ atom = $56\text{u}$
$\therefore$ Total number of $Fe$ atom $=\frac{224.48}{56}=4$.