Haemoglobin contains 0.334 % of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (Atomic weight of $F e$ is 56) present in one molecule of haemoglobin is:

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Solution

The correct option is A 4
Weight of $F e$ in haemoglobin
$= \frac{0.334}{100} \times 67200 = 224.48 u$
Mass of one $F e$ atom = $56 u$
$∴$ Total number of $F e$ atom $= \frac{224.48}{56} = 4$ .

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Q. Haemoglobin contains 0.334 % of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (Atomic weight of

F e

is 56) present in one molecule of haemoglobin is:

Haemoglobin contains 0.33% of iron by weight . The molecular weight of haemoglobin is approximately 67200 . The number of iron atoms ( at . wt. of Fe=56) present in one molecule of haemoglobin is

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Standard XII Chemistry

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Haemoglobin contains 0.334 % of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (Atomic weight of Fe is 56) present in one molecule of haemoglobin is:

The correct option is A 4Weight of Fe in haemoglobin =0.334100×67200=224.48 u Mass of one Fe atom = 56 u ∴ Total number of Fe atom =224.4856=4.

Haemoglobin contains 0.334 % of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (Atomic weight of $F e$ is 56) present in one molecule of haemoglobin is:

The correct option is A 4
Weight of $F e$ in haemoglobin
$= \frac{0.334}{100} \times 67200 = 224.48 u$
Mass of one $F e$ atom = $56 u$
$∴$ Total number of $F e$ atom $= \frac{224.48}{56} = 4$ .