Hailstones fall from a certain height. If only $1$ % of the hailstones melt on reaching the ground, find the height from which they fall. ( $g = 10 {m s}^{- 2}, L = 80$ calorie/g and $J = 4.2 J / c a l o r i e$ )

336 m

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236 m

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436 m

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536 m

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Solution

The correct option is A $336 m$
$L = 80 c a l / g = \frac{80 c a l}{10^{- 3}} = 80 \times 10^{3}$
1% of mass of hail stone melts
$∴ m g h = J \times \frac{1}{100} \times n \times L_{i c e}$
$h = \frac{J L}{100 \times g} = \frac{4.2 \times 80 \times 10^{3}}{100 \times 10} = 336 m$

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Hailstones fall from a certain height. If only 1% of the hailstones melt on reaching the ground, find the height from which they fall. (g=10ms−2,L=80 calorie/g and J=4.2J/calorie)

The correct option is A 336mL=80cal/g=80cal10−3=80×1031% of mass of hail stone melts∴mgh=J×1100×n×Liceh=JL100×g=4.2×80×103100×10=336m

Hailstones fall from a certain height. If only $1$ % of the hailstones melt on reaching the ground, find the height from which they fall. ( $g = 10 {m s}^{- 2}, L = 80$ calorie/g and $J = 4.2 J / c a l o r i e$ )

The correct option is A $336 m$
$L = 80 c a l / g = \frac{80 c a l}{10^{- 3}} = 80 \times 10^{3}$
1% of mass of hail stone melts
$∴ m g h = J \times \frac{1}{100} \times n \times L_{i c e}$
$h = \frac{J L}{100 \times g} = \frac{4.2 \times 80 \times 10^{3}}{100 \times 10} = 336 m$