Question

Half life of a certain radioactive element is 3.465 days. Find its disintegration constant.

Answer 1

$T_{1/2}=3.465$
Disintegration constant, $\lambda =\frac{lo{g}_{e}2}{T_{1/2}}$
$=\frac{0.6931}{3.465}$
$=\frac{0.6931}{3.465\times 24\times 60\times 60}$
$\lambda =2.32\times {10}^{-6}/sec.$