Half - lives of decomposition of $N H_{3}$ on the surface of a catalyst for different initial pressures are given as :
p(torr) 200 300 500
$t_{1.2 (m i n)}$ 10 15 25
The order of the reaction is :

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Solution

The correct option is B
0

$\frac{(t_{\frac{1}{2}})_{1}}{(t_{\frac{1}{2}})_{2}} = (\frac{a_{2}}{a_{1}})^{n - 1}; \frac{10}{15} = (\frac{300}{200})^{n - 1} o r, (\frac{2}{3})^{1} = (\frac{3}{2})^{n - 1} = (\frac{2}{3})^{1 - n}; 1 - n = 1, n = 0$

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Similar questions

Q. Half lives of decomposition of

N H_{3}

on a catalyst surface for difference initial pressure(P) are given as
P(atm) 200 300 500

t_{\frac{1}{2}}

(min) 10 15 25
Then, the order of the reaction is________.

Q. Half-life period for decomposition of

N H_{3}

over tungsten wire are given below:

Initial pressure in min	50	100	200
$t_{1 / 2}$	3.52	1.82	0.93

Order of the reaction is:

Half - lives of decomposition of $N H_{3}$ on the surface of a catalyst for different initial pressures are given as :
p(torr) 200 300 500
$t_{1.2 (m i n)}$ 10 15 25
The order of the reaction is :

Q. The half-lives against initial pressure are given below. Calculate the order of the reaction.

\begin{matrix} p (m m) & 750 & 500 & 250 t (m i n) & 105 & 235 & 950 \end{matrix}

Find out the order of the reaction.

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Half - lives of decomposition of NH3 on the surface of a catalyst for different initial pressures are given as : p(torr) 200 300 500 t1.2(min) 10 15 25 The order of the reaction is :

The correct option is B 0 (t12)1(t12)2=(a2a1)n−1;1015=(300200)n−1or,(23)1=(32)n−1=(23)1−n;1−n=1,n=0

Half - lives of decomposition of $N H_{3}$ on the surface of a catalyst for different initial pressures are given as :
p(torr) 200 300 500
$t_{1.2 (m i n)}$ 10 15 25
The order of the reaction is :

The correct option is B
0

$\frac{(t_{\frac{1}{2}})_{1}}{(t_{\frac{1}{2}})_{2}} = (\frac{a_{2}}{a_{1}})^{n - 1}; \frac{10}{15} = (\frac{300}{200})^{n - 1} o r, (\frac{2}{3})^{1} = (\frac{3}{2})^{n - 1} = (\frac{2}{3})^{1 - n}; 1 - n = 1, n = 0$