Question

# Half of the rectangular plate shown in figure is made of a material of density p1 and the other half of density p2. The length of the plate is L. Locate the centre of mass of the plate.

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is C The centre of mass of each half is located at the geometrical centre of that half. Thus, the left half may be replaced by a point particle of mass Kp1 placed at C1 and the right half may be replaced by a point particle of mass Kp2 placed at C2. This replacement is for the specific purpose of locating the combined centre of mass. Take the middle point of the left edge to be the origin. The x-coordinate of C1 is L4 and that of C2 is 3L4. Hence, the x-coordinate of the centre of mass is x = (Kp1)L4 + (Kp2)3L4Kp1 + Kp2 = (p1 + 3p2)4(p1 + p2)L. The combined centre of mass is this much to the right of the assumed origin.

Suggest Corrections
4
Join BYJU'S Learning Program
Select...
Related Videos
Just an Average Point?
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program
Select...