Question

Half the perimeter of a rectangular garden, whose length is 16 m more than its width, is 20 m. Find the dimensions of the garden.
(3 Marks)

Answer 1

Let the length of the garden be $x$ and the breadth be $y$.

Then, half the perimeter =$\frac{1}{2}\times 2(x+y)=20$

$\Rightarrow x+y=20\dots \left(1\right)\left(1Mark\right)$

Also given, length of garden is 16m more than its width.

$\Rightarrow x-y=16\dots \left(2\right)\left(1Mark\right)$

Adding (1) and (2),

$2x=36\Rightarrow x=18\left(0.5Marks\right)$

Substituting $x=18$ in (2),

$18-y=16\Rightarrow y=2\left(0.5Marks\right)$

$\therefore$ The length is 18 m and breadth is 2 m.