Question

Hamida purchased $3\frac{3}{5}$ litres of milk on Monday ,$3\frac{4}{5}$ litres on Tuesday and $6\frac{3}{10}$ on Wednesday.How much milk she purchase on three days?

Answer 1

Total amount of milk purchase by Hamida on three days $=$amount of milk purchase on Monday$+$amount of milk purchase on Tuesday$+$amount of milk purchase on Wednesday

$$\begin{gathered} =3\frac{3}{5}+3\frac{4}{5}+6\frac{3}{10} \\ =\frac{5x3+3}{5}+\frac{5x3+4}{5}+\frac{10x6+3}{10} \\ =\frac{15+3}{5}+\frac{15+4}{5}+\frac{60+3}{10} \\ =\frac{18}{5}+\frac{19}{5}+\frac{63}{10} \end{gathered}$$ Convert all the mixed fraction into improper fraction.

We can solve this by taking two terms together.

$$\begin{gathered} =\frac{18}{5}+\frac{19}{5}+\frac{63}{10} \\ =\frac{18+19}{5}+\frac{63}{10} \\ =\frac{37}{5}+\frac{63}{10} \\ =\frac{37x2+63}{10}LCMof5,10=10 \\ =\frac{74+63}{10} \\ =\frac{137}{10}convertintomixedfraction. \\ =13\frac{7}{10}litre. \end{gathered}$$

Hence total milk purchase by Hamida is $13\frac{7}{10}litres$.