Hansa travels on a carriage. It costs 10 dollars along with 3 dollars for every km. If she pays 55 dollars, the distance traveled is .

15 km

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

12 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 km

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 15 km
The cost = 10 dollars and 3 dollars for every kilometer.

Let x be the distance traveled.

$\Rightarrow$ 10 + 3x = 55

$\Rightarrow$ 3x = 55 - 10

$\Rightarrow$ 3x = 45

$\Rightarrow \frac{3 x}{3}$ = $\frac{45}{3}$

$\Rightarrow$ x = 15

Hence, the distance traveled is 15 kilometers.

Suggest Corrections

Similar questions

Q. If the train ride costs 55 cents and Snowball pays 3 dollars. She will get back as change.
( 1 dollar = 100 cents)

Q. Betty is at the arcade. It costs her 10 dollars to enter the arena.
Once she enters the arena, she can play as many games as she likes by paying 5 dollars for each game.
If she has a total of 50 dollars, how many games can she play?

Q. To get into the garden from the museum, you book a cab. After reaching the garden, you pay 45 dollars. If the fixed fare is 10 dollars and the fare per mile is 5 dollars, find the distance traveled from the museum to the garden.

Angel has 400 dollars in her savings account. She withdraws 20 dollars every week. She wants to have a minimum of 100 dollars at the end of year. If a year has "w" weeks, select the correct inequality for the given situation.

Q. Carcia had 21 dollars. If she spent 5 dollars, what is the ratio of dollars spent to the dollars she had before?

Join BYJU'S Learning Program

Hansa travels on a carriage. It costs 10 dollars along with 3 dollars for every km. If she pays 55 dollars, the distance traveled is .

The correct option is A 15 kmThe cost = 10 dollars and 3 dollars for every kilometer. Let x be the distance traveled. ⇒ 10 + 3x = 55 ⇒ 3x = 55 - 10 ⇒ 3x = 45 ⇒3x3 =453 ⇒ x = 15 Hence, the distance traveled is 15 kilometers.