Hardening of plaster of paris is because of ____________________ .

the formation of

C a C O_{3}

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the formation of

C a S i O_{3}

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the transition of orthorhombic gypsum to monoclinic gypsum

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dehydration

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Solution

The correct option is B the transition of orthorhombic gypsum to monoclinic gypsum
The plaster of paris absorbs water to form orthorhombic calcium sulfate dihydrate which sets to form a hard mass containing monoclinic calcium sulfate dihydrate.
$C a S O_{4} \cdot \frac{1}{2} H_{2} O s e t t i n g - --- \to w a t e r C a S O_{4} \cdot 2 H_{2} O h a r d e n i n g - ----- \to C a S O_{4} \cdot 2 H_{2} O$

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In hardening stage of plaster of paris, the change is

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