Question

Harry bought an ice cream. If (1/8) was chocolate, (5/12) was vanilla and (7/16) was mint and the rest was caramel. Then what fraction was caramel?

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

Fraction of chocolate icecream =$\frac{1}{8}$
Vanilla ice cream =$\frac{5}{12}$
Mint ice cream =$\frac{7}{16}$
Remaining =caramel.
$\therefore$ Fraction of caramel ice cream
=$\frac{1}{8}+\frac{5}{12}+\frac{7}{16}$
LCM = 48
$\frac{1^{x6}}{8}+\frac{5^{x4}}{12}+\frac{7^{x3}}{16}=\frac{6+20+21}{48}$ $2\times 2\times 2\times 3\times 2$
=48
=$\frac{47}{48}$
$\therefore$ Caramel = $1-\frac{47}{48}$
LCM=$\frac{1^{x48}}{1}-\frac{47}{48}$
LCM 1 and 48
=48
$\frac{48-47}{48}=\frac{1}{48}$