Question

has the same value as cot ${53}^{\circ }$

• A. $tan{47}^{\circ }$
• B. $tan{37}^{\circ }$
• C. $cot{37}^{\circ }$

Answer 1

The correct option is B $tan{37}^{\circ }$

We know that
$cot\theta =tan({90}^{\circ }-\theta )$
$\therefore cot{53}^{\circ }=tan({90}^{\circ }-{53}^{\circ })\Rightarrow cot{53}^{\circ }=tan{37}^{\circ }$.