HBr reacts slowest with

C_{6} H_{5} C H_{2} O H

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P - O_{2} N C_{6} H_{4} C H_{2} O H

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P - C H_{3} O C_{6} H_{4} C H_{2} O H

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P - C l C_{6} H_{4} C H_{2} O H

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Solution

The correct option is B $P - O_{2} N C_{6} H_{4} C H_{2} O H$
The electron withdrawing group makes the reaction slowest.
Thus, $P - O_{2} N C_{6} H_{4} C H_{2} O H$ reacts slowest.

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