Question

HCF by Euclid division method HCF by Euclid division method of 265 65, 2580 6, 20930

Answer 1

Dear Student
$$\begin{gathered} Eucliddivisionlemma \\ a=bq+r \\ 26565,25806,20930 \\ 26565=25806\times 1+759 \\ 25806=759\times 34+0 \\ 20930=759\times 27+437 \\ 759=437\times 1+322 \\ 437=322\times 1+115 \\ 322=115\times 2+92 \\ 115=92\times 1+23 \\ 92=23\times 4+0 \\ henceHCFof26565,25806and20930is23. \end{gathered}$$
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