Question

$HCF$ of $(10224,1608)$ is _________.

• A. $12$
• B. $24$
• C. $48$
• D. $96$

Answer 1

The correct option is B $24$

First step is to write $10224$ and $1608$ as the product of its prime factors.

$10224=2^4\times 3^2\times 71$

$1608=2^3\times 3\times 67$

$\therefore HCF(10224,1608)=2^3\times 3$

$=24$