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Byju's Answer
Standard VIII
Mathematics
Factorisation by Common Factors
HCF of 126 an...
Question
HCF of 126 and 35 is H and H= 126*A+35*B so show that A*B/H=-2
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Solution
126
=
2
×
3
×
3
×
7
35
=
5
×
7
HCF
of
126
and
35
=
7
Therefore
,
7
=
126
A
+
35
B
⇒
7
=
7
18
A
+
5
B
⇒
1
=
18
A
+
5
B
It
is
true
for
A
=
2
and
B
=
-
7
Now
,
A
×
B
H
=
2
×
-
7
7
=
-
2
Hence
,
proved
.
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