HCF of 23-32-5-22-33-52-and-24-3-53-7 is a 30 b 48 c 60 d105

Answer : (c) 60 HCF = 2^3 × 3^2 × 5, 2^2 × 3^3 × 5^2, 2^4 ×3 × 5^3 × 7 HCF = Product of smallest power of each common prime factor in the numbers = 2^ ...

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Byju's Answer

Standard X

Mathematics

Method of Finding HCF

HCF of 23×32×...

Question

HCF of $(2^{3} \times 3^{2} \times 5), (2^{2} \times 3^{3} \times 5^{2}) a n d (2^{4} \times 3 \times 5^{3} \times 7)$ is

(a) 30 (b) 48 (c) 60 (d)105

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Solution

Answer : (c) 60

HCF = $2^{3} \times 3^{2} \times 5, 2^{2} \times 3^{3} \times 5^{2}, 2^{4} \times 3 \times 5^{3} \times 7$
HCF = Product of smallest power of each common prime factor in the numbers
= $2^{2} \times 3 \times 5$
= 60

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Similar questions

Q. HCF of (2³ × 3² × 5), (2² × 3³ ×5²) and (2⁴ ×³× 5³ × 7) is

(a) 30
(b) 48
(c) 60
(d) 105

Q. If a =

2^{3} \times 3^{3} \times 7^{2}

and

b = 2^{2} \times 3^{2} \times 5^{3},

which is true?

If $a = 2^{3} \times 3^{2} \times 5$ and $b = 2^{4} \times 3 \times 7^{2}$ , then which of the following is true?

Q. Simplify:

\frac{2^{3} \times 3^{2} \times 5^{4}}{3^{3} \times 5^{2} \times 2^{4}}

If $a = (2^{2} \times 3^{3} \times 5^{4}) and b = (2^{3} \times 3^{2} \times 5)$ then, HCF of $(a, b)$ is ____.

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HCF of (23×32×5),(22×33×52) and (24×3×53×7) is (a) 30 (b) 48 (c) 60 (d)105

Answer : (c) 60 HCF = 23×32×5,22×33×52,24×3×53×7 HCF = Product of smallest power of each common prime factor in the numbers = 22×3×5 = 60

HCF of $(2^{3} \times 3^{2} \times 5), (2^{2} \times 3^{3} \times 5^{2}) a n d (2^{4} \times 3 \times 5^{3} \times 7)$ is

(a) 30 (b) 48 (c) 60 (d)105

Answer : (c) 60

HCF = $2^{3} \times 3^{2} \times 5, 2^{2} \times 3^{3} \times 5^{2}, 2^{4} \times 3 \times 5^{3} \times 7$
HCF = Product of smallest power of each common prime factor in the numbers
= $2^{2} \times 3 \times 5$
= 60