HCF of co-prime numbers 4 and 15 was found as follows by factorisation- 4 - 2 - 2 and 15 - 3 - 5 Since there is no common prime factor- HCF of 4 and 15 is 0- Is the answer correct- If not- what is the correct HCF-

THe answer is wrong because , #160; 4=2× 2× 1 and #160; 15=3× 5× 1 #160;So, highest common factor will be 1 and not 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Method of Finding HCF

HCF of co-pri...

Question

$H C F$ of co-prime numbers $4$ and $15$ was found as follows by factorisation: $4 = 2 \times 2$ and $15 = 3 \times 5$ Since there is no common prime factor, $H C F$ of $4$ and $15$ is $0$ . Is the answer correct? If not, what is the correct $H C F$ ?

Open in App

Solution

THe answer is wrong because ,
$4 = 2 \times 2 \times 1$ and
$15 = 3 \times 5 \times 1$
So, highest common factor will be $1$ and not $0$

Suggest Corrections

Similar questions

Question 3

HCF of co-prime numbers 4 and 15 was found as follows by factorization: $4 = 2 \times 2$ and $15 = 3 \times 5$ . Since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Q. H.C.F of co-prime numbers 4 and 15 was found as follow:
4=2

\times

2 and 15=3

\times

5
Since there is no common prime factor. So, H.C.F of 4 and 15 is 0. Is the answer correct? If not, what is the correct H.C.F?

Find the LCM and HCF of 12, 15 and 21 by applying the prime factorization method. [2 MARKS]

Question 26
Which of the following statements is not true?

(A) The HCF of two distinct prime numbers is 1
(B) The HCF of two co-prime numbers is 1
(C) The HCF of two consecutive even numbers is 2
(D) The HCF of an even and an odd number is even.

Join BYJU'S Learning Program

HCF of co-prime numbers 4 and 15 was found as follows by factorisation: 4=2×2 and 15=3×5 Since there is no common prime factor, HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

THe answer is wrong because , 4=2×2×1 and 15=3×5×1 So, highest common factor will be 1 and not 0

$H C F$ of co-prime numbers $4$ and $15$ was found as follows by factorisation: $4 = 2 \times 2$ and $15 = 3 \times 5$ Since there is no common prime factor, $H C F$ of $4$ and $15$ is $0$ . Is the answer correct? If not, what is the correct $H C F$ ?

THe answer is wrong because ,
$4 = 2 \times 2 \times 1$ and
$15 = 3 \times 5 \times 1$
So, highest common factor will be $1$ and not $0$