HCF of co-prime numbers 4 and 15 was found as follows by fatorisation- 4 - 2 - 2 and 15 - 3 - 5 since there is no common prime factor- so HCF of 4 and 15 is 0- Is the answer correct- If not- what is the correct HCF-

H.C.F of 4 ,15≠ 0 Factors of 4=2× 2× 1 Factors of 15=3× 5× 1 ∴ H.C.F =1 is the correct H.C.F ...

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Standard VI

Mathematics

HCF

HCF of co-pri...

Question

HCF of co-prime numbers 4 and 15 was found as follows by fatorisation:
$4 = 2 \times 2 a n d 15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

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Solution

H.C.F of $4, 15 \neq 0$
Factors of $4 = 2 \times 2 \times 1$
Factors of $15 = 3 \times 5 \times 1$
$∴$ H.C.F $= 1$ is the correct H.C.F

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Question 3

HCF of co-prime numbers 4 and 15 was found as follows by factorization: $4 = 2 \times 2$ and $15 = 3 \times 5$ . Since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Q. H.C.F of co-prime numbers 4 and 15 was found as follow:
4=2

\times

2 and 15=3

\times

5
Since there is no common prime factor. So, H.C.F of 4 and 15 is 0. Is the answer correct? If not, what is the correct H.C.F?

Question 26
Which of the following statements is not true?

(A) The HCF of two distinct prime numbers is 1
(B) The HCF of two co-prime numbers is 1
(C) The HCF of two consecutive even numbers is 2
(D) The HCF of an even and an odd number is even.

Find the LCM and HCF of 12, 15 and 21 by applying the prime factorization method. [2 MARKS]

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HCF of co-prime numbers 4 and 15 was found as follows by fatorisation:4=2×2and15=3×5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

H.C.F of 4,15≠0Factors of 4=2×2×1Factors of 15=3×5×1∴ H.C.F=1 is the correct H.C.F

HCF of co-prime numbers 4 and 15 was found as follows by fatorisation:
$4 = 2 \times 2 a n d 15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

H.C.F of $4, 15 \neq 0$
Factors of $4 = 2 \times 2 \times 1$
Factors of $15 = 3 \times 5 \times 1$
$∴$ H.C.F $= 1$ is the correct H.C.F