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Question

HCF of (x29) and (x+3)2 is 'a'. HCF of x2+x6 and x24 is 'b'. Then a×b is ____.


A

x2+x8

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B

x2+x6

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C

x2x6

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D

x3+x6

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Solution

The correct option is B

x2+x6


Let us factorize the given expressions.

x29=x232=(x+3)(x3)

(x+3)2=(x+3)(x+3)

So, the HCF, a=(x+3)

x2+x6=(x+3)(x2)

x24=(x+2)(x2)

So, the HCF, b=(x2)

Hence, a×b=(x+3)(x2)=x2+x6


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