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Question

HCF of x3y5z3, x2y4z2 and x2y2z2 is xaybzc. a+b+c = _______________


A

8

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B

4

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C

6

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D

5

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Solution

The correct option is C

6


Given expressions x3y5z3, x2y4z2 and x2y2z2

Power of 'x' which divides all expressions = 2

Power of 'y' which divides all expressions = 2

Power of 'z' which divides all expressions = 2

HCF xaybzc = x2y2z2

a=2,b=2,c=2

a+b+c = 6


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