Question

HCF of $x^3{y}^5{z}^3$, $x^2{y}^4{z}^2$ and $x^2{y}^2{z}^2$ is $x^a{y}^b{z}^c$. Then $a+b+c$ = .

• A. 8
• B. 4
• C. 6
• D. 5

Answer 1

The correct option is C 6

Given expressions are $x^3{y}^5{z}^3$, $x^2{y}^4{z}^2$ and $x^2{y}^2{z}^2$.

Power of 'x' which divides all the expressions = $x^2$

Power of 'y' which divides all the expressions = $y^2$

Power of 'z' which divides all the expressions = $z^2$

Hence, HCF, $x^a{y}^b{z}^c$ = $x^2{y}^2{z}^2$

$⟹a=2,b=2,c=2$

$\therefore a+b+c$ = 6