HCF of $x^{6} y^{4} z^{2}$ , $x^{6} y^{4} z^{6}$ and $x^{7} y^{9} z^{4}$ is $x^{a} y^{b} z^{c}$ . a-b-c = ___

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Solution

Given expressions $x^{6} y^{4} z^{2}$ , $x^{6} y^{4} z^{6}$ and $x^{7} y^{9} z^{4}$

Power of 'x' which divides all expressions 6

Power of 'y' which divides all expressions 4

Power of 'z' which divides all expressions 2

HCF $x^{a} y^{b} z^{c}$ = $x^{5} y^{4} z^{2}$

$a = 6, b = 4, c = 2$

$a - b - c$ = 0

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