HCF of $x^{6} y^{4} z^{2}$ , $x^{6} y^{4} z^{6}$ and $x^{7} y^{9} z^{4}$ is $x^{a} y^{b} z^{c}$ . Then $a - b - c$ = .

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Solution

The correct option is A 0.0
Given expressions are $x^{6} y^{4} z^{2}$ , $x^{6} y^{4} z^{6}$ and $x^{7} y^{9} z^{4}$ .

Exponent of 'x' which divides all the expressions is 6.

Exponent of 'y' which divides all the expressions is 4.

Exponent of 'z' which divides all the expressions is 2.

Hence, HCF, $x^{a} y^{b} z^{c}$ = $x^{5} y^{4} z^{2}$

So, $a = 6, b = 4, c = 2$

$∴ a - b - c = 0$

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