$H C H O$ and $H C O O H$ are detected by

N a H {C O}_{3}

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C u {S O}_{4} / N a O H

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A g {N O}_{3} / {N H}_{4} O H

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All of these

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Solution

The correct option is B $N a H {C O}_{3}$
Both $H C H O$ and $H C O O H$ react with $A g {N O}_{3} / {N H}_{4} O H$
$C u {S O}_{4} / N a O H$ solution. But $H C O O H$ gives effervescences of ${C O}_{2}$ when reacts with $N a H {C O}_{3}$ , whereas $H C H O$ does not give any effervescence of ${C O}_{2}$ when reacts with $N a H {C O}_{3}$ .
$H C O O H + N a H {C O}_{3} ⟶ H C O O N a + H_{2} O + {C O}_{2} ↑$

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A g N O_{3}

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H I O_{4}

K l

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A g N O_{3}

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