HCHO and HCOOH are distinguished by treating with:

Tollen’s reagent

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NaHCO₃

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Fehling’s solution

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Benedict solution

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Solution

The correct option is B NaHCO₃
$H C O O H$ reacts with $N a H C O_{3}$ producing effervescence of $C O_{2}$ but not $H C H O$ .

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N a_{2} C O_{3}

N a H C O_{3}

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H C H O

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H I O_{4}

H C O O H

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N a_{2} C O_{3}

N a H C O_{3}

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